If it's not what You are looking for type in the equation solver your own equation and let us solve it.
-5t^2+50t-80=0
a = -5; b = 50; c = -80;
Δ = b2-4ac
Δ = 502-4·(-5)·(-80)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-30}{2*-5}=\frac{-80}{-10} =+8 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+30}{2*-5}=\frac{-20}{-10} =+2 $
| 4z-2+6z=18 | | 14+6x=8x+8 | | 1.2=–3b | | 14+4(x-5)=6-2× | | P=0.8x-500 | | 0.5+10=z+4 | | 16c+5c-20c+1=16 | | 14x-12=-12 | | -3x+6-5(x-1)=-(2x+4)-5x+5 | | n/3-4=-4 | | 7y-9-2+5=0 | | b+(3/16)=5/16 | | x/7=67 | | -2k-6k=-7k | | 14x+12=-12 | | b+(3/16)=(5/16) | | 5b-13=-28 | | 20h−20h+3h=15 | | 6(x+3)-2)7x-3)=17 | | 6m^2+21m=0 | | r+-9r-4=20 | | 3/4(12x+4)=10 | | r+-9r−-4=20 | | x+-4=-13 | | 24=-3h+23h | | 18x^2-39+20=0 | | 8y-5y-2=16-3y | | -4-(x)=-2 | | 5/y+4=-8 | | 2h+2=5h+2 | | 36r/4=7 | | -6=-3(g−5) |